(3)/(x-5)+(22)/(5x-25)

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Solution for (3)/(x-5)+(22)/(5x-25) equation: 


D( x )

x-5 = 0

5*x-25 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

5*x-25 = 0

5*x-25 = 0

5*x-25 = 0 // + 25

5*x = 25 // : 5

x = 25/5

x = 5

x in (-oo:5) U (5:+oo)

3/(x-5)+22/(5*x-25) = 0

(3*(5*x-25))/((x-5)*(5*x-25))+(22*(x-5))/((x-5)*(5*x-25)) = 0

3*(5*x-25)+22*(x-5) = 0

37*x-185 = 0

(37*x-185)/((x-5)*(5*x-25)) = 0

(37*x-185)/((x-5)*(5*x-25)) = 0 // * (x-5)*(5*x-25)

37*x-185 = 0

37*x-185 = 0 // + 185

37*x = 185 // : 37

x = 185/37

x = 5

x in { 5} 

x belongs to the empty set

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