(6x-12/x-10)-(4x+8/x-10)

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Solution for (6x-12/x-10)-(4x+8/x-10) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6*x-(4*x)-(12/x)-(8/x)-10+10 = 0

6*x-4*x-12*x^-1-8*x^-1-10+10 = 0

2*x^1-20*x^-1 = 0

(2*x^2-20*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-20*x^0) = 0

x^1

2*x^2-20 = 0

2*x^2-20 = 0

DELTA = 0^2-(-20*2*4)

DELTA = 160

DELTA > 0

x = (160^(1/2)+0)/(2*2) or x = (0-160^(1/2))/(2*2)

x = 10^(1/2) or x = -10^(1/2)

x in { -10^(1/2), 10^(1/2)}

x in { -10^(1/2), 10^(1/2) }

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