(3(x+1))/6=2x-1

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Solution for (3(x+1))/6=2x-1 equation: 



(3(x+1))/6=2x-1

We move all terms to the left:

(3(x+1))/6-(2x-1)=0

We get rid of parentheses

(3(x+1))/6-2x+1=0

We multiply all the terms by the denominator


(3(x+1))-2x*6+1*6=0



We calculate terms in parentheses: +(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

+(3x+3)



We add all the numbers together, and all the variables

(3x+3)-2x*6+6=0

Wy multiply elements

(3x+3)-12x+6=0

We get rid of parentheses

3x-12x+3+6=0

We add all the numbers together, and all the variables

-9x+9=0

We move all terms containing x to the left, all other terms to the right

-9x=-9

x=-9/-9

x=1

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