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2x*x-5=12
We move all terms to the left:
2x*x-5-(12)=0
We add all the numbers together, and all the variables
2x*x-17=0
Wy multiply elements
2x^2-17=0
a = 2; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·2·(-17)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{34}}{2*2}=\frac{0-2\sqrt{34}}{4} =-\frac{2\sqrt{34}}{4} =-\frac{\sqrt{34}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{34}}{2*2}=\frac{0+2\sqrt{34}}{4} =\frac{2\sqrt{34}}{4} =\frac{\sqrt{34}}{2} $
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