(3(x+1))/4=x+2

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Solution for (3(x+1))/4=x+2 equation: 



(3(x+1))/4=x+2

We move all terms to the left:

(3(x+1))/4-(x+2)=0

We get rid of parentheses

(3(x+1))/4-x-2=0

We multiply all the terms by the denominator


(3(x+1))-x*4-2*4=0



We calculate terms in parentheses: +(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

+(3x+3)



We add all the numbers together, and all the variables

(3x+3)-x*4-8=0

Wy multiply elements

(3x+3)-4x-8=0

We get rid of parentheses

3x-4x+3-8=0

We add all the numbers together, and all the variables

-1x-5=0

We move all terms containing x to the left, all other terms to the right

-x=5

x=5/-1

x=-5

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