(4(x+4))/5=-4-x

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Solution for (4(x+4))/5=-4-x equation: 



(4(x+4))/5=-4-x

We move all terms to the left:

(4(x+4))/5-(-4-x)=0

We add all the numbers together, and all the variables

(4(x+4))/5-(-1x-4)=0

We get rid of parentheses

(4(x+4))/5+1x+4=0

We multiply all the terms by the denominator


(4(x+4))+1x*5+4*5=0



We calculate terms in parentheses: +(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

+(4x+16)



We add all the numbers together, and all the variables

(4x+16)+1x*5+20=0

Wy multiply elements

(4x+16)+5x+20=0

We get rid of parentheses

4x+5x+16+20=0

We add all the numbers together, and all the variables

9x+36=0

We move all terms containing x to the left, all other terms to the right

9x=-36

x=-36/9

x=-4

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