(2y+3y+3)2=116

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Solution for (2y+3y+3)2=116 equation:



(2y+3y+3)2=116
We move all terms to the left:
(2y+3y+3)2-(116)=0
We add all the numbers together, and all the variables
(5y+3)2-116=0
We multiply parentheses
10y+6-116=0
We add all the numbers together, and all the variables
10y-110=0
We move all terms containing y to the left, all other terms to the right
10y=110
y=110/10
y=11

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