(2y+3)=(4y-27)

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Solution for (2y+3)=(4y-27) equation: 



(2y+3)=(4y-27)

We move all terms to the left:

(2y+3)-((4y-27))=0

We get rid of parentheses

2y-((4y-27))+3=0



We calculate terms in parentheses: -((4y-27)), so:

(4y-27)

We get rid of parentheses

4y-27

Back to the equation:

-(4y-27)



We get rid of parentheses

2y-4y+27+3=0

We add all the numbers together, and all the variables

-2y+30=0

We move all terms containing y to the left, all other terms to the right

-2y=-30

y=-30/-2

y=+15

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