(2y+3)/y=3/2

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Solution for (2y+3)/y=3/2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(2*y+3)/y = 3/2 // - 3/2

(2*y+3)/y-(3/2) = 0

(2*y+3)/y-3/2 = 0

(2*(2*y+3))/(2*y)+(-3*y)/(2*y) = 0

2*(2*y+3)-3*y = 0

y+6 = 0

(y+6)/(2*y) = 0

(y+6)/(2*y) = 0 // * 2*y

y+6 = 0

y+6 = 0 // - 6

y = -6

y = -6

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