2y+3/y=3/2

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Solution for 2y+3/y=3/2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

2*y+3/y = 3/2 // - 3/2

2*y+3/y-(3/2) = 0

2*y+3/y-3/2 = 0

2*y^1+3*y^-1-3/2*y^0 = 0

(2*y^2-3/2*y^1+3*y^0)/(y^1) = 0 // * y^2

y^1*(2*y^2-3/2*y^1+3*y^0) = 0

y^1

2*y^2+(-3/2)*y+3 = 0

2*y^2+(-3/2)*y+3 = 0

DELTA = (-3/2)^2-(2*3*4)

DELTA = -87/4

DELTA < 0

y in { } 

y belongs to the empty set

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