(2y+3)+3(y+2)=40

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Solution for (2y+3)+3(y+2)=40 equation: 



(2y+3)+3(y+2)=40

We move all terms to the left:

(2y+3)+3(y+2)-(40)=0

We multiply parentheses

(2y+3)+3y+6-40=0

We get rid of parentheses

2y+3y+3+6-40=0

We add all the numbers together, and all the variables

5y-31=0

We move all terms containing y to the left, all other terms to the right

5y=31

y=31/5

y=6+1/5

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