(4x+6)(7x+2)=0

Solution for (4x+6)(7x+2)=0 equation:

(4x+6)(7x+2)=0

We multiply parentheses ..

(+28x^2+8x+42x+12)=0

We get rid of parentheses

28x^2+8x+42x+12=0

We add all the numbers together, and all the variables

28x^2+50x+12=0

a = 28; b = 50; c = +12;
Δ = b2-4ac
Δ = 502-4·28·12
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-34}{2*28}=\frac{-84}{56}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+34}{2*28}=\frac{-16}{56}
=-2/7
$