(2y+1)/3=y-1/2

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Solution for (2y+1)/3=y-1/2 equation: 



(2y+1)/3=y-1/2

We move all terms to the left:

(2y+1)/3-(y-1/2)=0

We add all the numbers together, and all the variables

(2y+1)/3-(+y-1/2)=0

We get rid of parentheses

(2y+1)/3-y+1/2=0

We calculate fractions

There is no solution for this equation

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