(2y+1)/3=(1-y)/4

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Solution for (2y+1)/3=(1-y)/4 equation: 



(2y+1)/3=(1-y)/4

We move all terms to the left:

(2y+1)/3-((1-y)/4)=0

We add all the numbers together, and all the variables

(2y+1)/3-((-1y+1)/4)=0

We calculate fractions


2y/()+(-((-1y+1)*3)/()=0



We calculate terms in parentheses: +(-((-1y+1)*3)/(), so:

-((-1y+1)*3)/(

We multiply all the terms by the denominator


-((-1y+1)*3)



We calculate terms in parentheses: -((-1y+1)*3), so:

(-1y+1)*3

We multiply parentheses

-3y+3

Back to the equation:

-(-3y+3)



We get rid of parentheses

3y-3

Back to the equation:

+(3y-3)



We get rid of parentheses

2y/()+3y-3=0

We multiply all the terms by the denominator


2y+3y*()-3*()=0

We add all the numbers together, and all the variables

2y+3y*()=0

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