12(x-4)=10(x-3)x+5

Solution for 12(x-4)=10(x-3)x+5 equation:

12(x-4)=10(x-3)x+5

We move all terms to the left:

12(x-4)-(10(x-3)x+5)=0

We multiply parentheses

12x-(10(x-3)x+5)-48=0


We calculate terms in parentheses: -(10(x-3)x+5), so:

10(x-3)x+5

We multiply parentheses

10x^2-30x+5

Back to the equation:

-(10x^2-30x+5)


We get rid of parentheses

-10x^2+12x+30x-5-48=0

We add all the numbers together, and all the variables

-10x^2+42x-53=0

a = -10; b = 42; c = -53;
Δ = b2-4ac
Δ = 422-4·(-10)·(-53)
Δ = -356
Delta is less than zero, so there is no solution for the equation