(2y+1)+4y=7

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Solution for (2y+1)+4y=7 equation: 



(2y+1)+4y=7

We move all terms to the left:

(2y+1)+4y-(7)=0

We add all the numbers together, and all the variables

4y+(2y+1)-7=0

We get rid of parentheses

4y+2y+1-7=0

We add all the numbers together, and all the variables

6y-6=0

We move all terms containing y to the left, all other terms to the right

6y=6

y=6/6

y=1

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