8=(-22/5)x-(-12)

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Solution for 8=(-22/5)x-(-12) equation: 



8=(-22/5)x-(-12)

We move all terms to the left:

8-((-22/5)x-(-12))=0



Domain of the equation: 5)x-(-12))!=0

x∈R



We multiply all the terms by the denominator


-((-22+8*5)x-(-12))=0



We calculate terms in parentheses: -((-22+8*5)x-(-12)), so:

(-22+8*5)x-(-12)

We add all the numbers together, and all the variables

18x-(-12)

We add all the numbers together, and all the variables

18x+12

Back to the equation:

-(18x+12)



We get rid of parentheses

-18x-12=0

We move all terms containing x to the left, all other terms to the right

-18x=12

x=12/-18

x=-2/3

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