(2x=3)+(x+1)

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Solution for (2x=3)+(x+1) equation: 



(2x=3)+(x+1)

We move all terms to the left:

(2x-(3)+(x+1))=0



We calculate terms in parentheses: +(2x-3+(x+1)), so:

2x-3+(x+1)

determiningTheFunctionDomain
2x+(x+1)-3

We get rid of parentheses

2x+x+1-3

We add all the numbers together, and all the variables

3x-2

Back to the equation:

+(3x-2)



We get rid of parentheses

3x-2=0

We move all terms containing x to the left, all other terms to the right

3x=2

x=2/3

x=2/3

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