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x+6=1/3x+1.5
We move all terms to the left:
x+6-(1/3x+1.5)=0
Domain of the equation: 3x+1.5)!=0We get rid of parentheses
x∈R
x-1/3x-1.5+6=0
We multiply all the terms by the denominator
x*3x-(1.5)*3x+6*3x-1=0
We multiply parentheses
x*3x-4.5x+6*3x-1=0
Wy multiply elements
3x^2-4.5x+18x-1=0
We add all the numbers together, and all the variables
3x^2+13.5x-1=0
a = 3; b = 13.5; c = -1;
Δ = b2-4ac
Δ = 13.52-4·3·(-1)
Δ = 194.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13.5)-\sqrt{194.25}}{2*3}=\frac{-13.5-\sqrt{194.25}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13.5)+\sqrt{194.25}}{2*3}=\frac{-13.5+\sqrt{194.25}}{6} $
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