(2x2+5)(3x2=4x+1)

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Solution for (2x2+5)(3x2=4x+1) equation: 



(2x^2+5)(3x^2=4x+1)

We move all terms to the left:

(2x^2+5)(3x^2-(4x+1))=0



We calculate terms in parentheses: +(2x^2+5)(3x^2-(4x+1)), so:

2x^2+5)(3x^2-(4x+1)

We get rid of parentheses

2x^2+5)(3x^2-4x-1

We add all the numbers together, and all the variables

2x^2-4x+5)(3x^2-1

Back to the equation:

+(2x^2-4x+5)(3x^2-1)

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