7/3x+1/3x=1(5/3x)

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Solution for 7/3x+1/3x=1(5/3x) equation: 



7/3x+1/3x=1(5/3x)

We move all terms to the left:

7/3x+1/3x-(1(5/3x))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

7/3x+1/3x-(1(+5/3x))=0

We calculate fractions


3x/9x^2+(-(1(+5*3x)/9x^2=0

We multiply all the terms by the denominator


3x+(-(1(+5*3x)=0



We calculate terms in parentheses: +(-(1(+5*3x), so:

-(1(+5*3x





We calculate terms in parentheses: +(-(1(+5*3x), so:

-(1(+5*3x





We calculate terms in parentheses: +(-(1(+5*3x), so:

-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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-(1(+5*3x





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