(2x/7)=(7/11)

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Solution for (2x/7)=(7/11) equation:



(2x/7)=(7/11)
We move all terms to the left:
(2x/7)-((7/11))=0
We add all the numbers together, and all the variables
(+2x/7)-((+7/11))=0
We get rid of parentheses
2x/7-((+7/11))=0
We calculate fractions
22x^2/()+()/()=0
We add all the numbers together, and all the variables
22x^2/()+1=0
We multiply all the terms by the denominator
22x^2+1*()=0
We add all the numbers together, and all the variables
22x^2=0
a = 22; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·22·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{44}=0$

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