(2x-9)+(3x+12)=2x+78

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Solution for (2x-9)+(3x+12)=2x+78 equation: 



(2x-9)+(3x+12)=2x+78

We move all terms to the left:

(2x-9)+(3x+12)-(2x+78)=0

We get rid of parentheses

2x+3x-2x-9+12-78=0

We add all the numbers together, and all the variables

3x-75=0

We move all terms containing x to the left, all other terms to the right

3x=75

x=75/3

x=25

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