2+5(x+4)=8-3(x-9)+6x

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Solution for 2+5(x+4)=8-3(x-9)+6x equation: 



2+5(x+4)=8-3(x-9)+6x

We move all terms to the left:

2+5(x+4)-(8-3(x-9)+6x)=0

We multiply parentheses

5x-(8-3(x-9)+6x)+20+2=0



We calculate terms in parentheses: -(8-3(x-9)+6x), so:

8-3(x-9)+6x

determiningTheFunctionDomain
-3(x-9)+6x+8

We add all the numbers together, and all the variables

6x-3(x-9)+8

We multiply parentheses

6x-3x+27+8

We add all the numbers together, and all the variables

3x+35

Back to the equation:

-(3x+35)



We add all the numbers together, and all the variables

5x-(3x+35)+22=0

We get rid of parentheses

5x-3x-35+22=0

We add all the numbers together, and all the variables

2x-13=0

We move all terms containing x to the left, all other terms to the right

2x=13

x=13/2

x=6+1/2

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