(2x-7)/7=(x+3)/3

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Solution for (2x-7)/7=(x+3)/3 equation: 



(2x-7)/7=(x+3)/3

We move all terms to the left:

(2x-7)/7-((x+3)/3)=0

We calculate fractions


2x/()+(-((x+3)*7)/()=0



We calculate terms in parentheses: +(-((x+3)*7)/(), so:

-((x+3)*7)/(

We multiply all the terms by the denominator


-((x+3)*7)



We calculate terms in parentheses: -((x+3)*7), so:

(x+3)*7

We multiply parentheses

7x+21

Back to the equation:

-(7x+21)



We get rid of parentheses

-7x-21

Back to the equation:

+(-7x-21)



We get rid of parentheses

2x/()-7x-21=0

We multiply all the terms by the denominator


2x-7x*()-21*()=0

We add all the numbers together, and all the variables

2x-7x*()=0

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