(2x-7)/4=(3x+4)/6

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Solution for (2x-7)/4=(3x+4)/6 equation: 



(2x-7)/4=(3x+4)/6

We move all terms to the left:

(2x-7)/4-((3x+4)/6)=0

We calculate fractions


2x/()+(-((3x+4)*4)/()=0



We calculate terms in parentheses: +(-((3x+4)*4)/(), so:

-((3x+4)*4)/(

We multiply all the terms by the denominator


-((3x+4)*4)



We calculate terms in parentheses: -((3x+4)*4), so:

(3x+4)*4

We multiply parentheses

12x+16

Back to the equation:

-(12x+16)



We get rid of parentheses

-12x-16

Back to the equation:

+(-12x-16)



We get rid of parentheses

2x/()-12x-16=0

We multiply all the terms by the denominator


2x-12x*()-16*()=0

We add all the numbers together, and all the variables

2x-12x*()=0

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