If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2x-7)(3x-7)=0
We multiply parentheses ..
(+6x^2-14x-21x+49)=0
We get rid of parentheses
6x^2-14x-21x+49=0
We add all the numbers together, and all the variables
6x^2-35x+49=0
a = 6; b = -35; c = +49;
Δ = b2-4ac
Δ = -352-4·6·49
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-7}{2*6}=\frac{28}{12} =2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+7}{2*6}=\frac{42}{12} =3+1/2 $
| 9x-15=10x+9 | | 1/3x-1=2*(1/3x+1/5) | | 40+14a=2(-4a-13) | | 40+14a=2(−4a−13) | | C=2(3.14159265359)r | | -5v-4=-6v-(1-v) | | 1/2*1/50=n | | c+7+3c=5c=+11 | | -12+2x+x^2=0 | | 1/2u=25 | | (2x×x)=210 | | 1.9+x=2.7 | | 27y=1 | | N+6=9x7 | | 2/3y-1/5(y-21/2)=51/3 | | h=15-4h | | 2(3x-2)-5=15-(x+3) | | 2(3x-2)-5=15-(x+3 | | 8^(x^2+2x-8)=64 | | a=7X4 | | 5(b-3)-2(b-1)=-6 | | X+(2x×x)=210 | | a=7.4 | | 44=4v | | 3g=-2(4g+11) | | R=r/12 | | 0.3/x=0.1 | | v=18+6+4 | | 2(-7)=d | | v=13+45 | | V=13+9x5 | | 2(-7)+7=y |