5(b-3)-2(b-1)=-6

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Solution for 5(b-3)-2(b-1)=-6 equation:



5(b-3)-2(b-1)=-6
We move all terms to the left:
5(b-3)-2(b-1)-(-6)=0
We add all the numbers together, and all the variables
5(b-3)-2(b-1)+6=0
We multiply parentheses
5b-2b-15+2+6=0
We add all the numbers together, and all the variables
3b-7=0
We move all terms containing b to the left, all other terms to the right
3b=7
b=7/3
b=2+1/3

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