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(2x-6)/3=(x+8)/2
We move all terms to the left:
(2x-6)/3-((x+8)/2)=0
We calculate fractions
2x/()+(-((x+8)*3)/()=0
We calculate terms in parentheses: +(-((x+8)*3)/(), so:We get rid of parentheses
-((x+8)*3)/(
We multiply all the terms by the denominator
-((x+8)*3)
We calculate terms in parentheses: -((x+8)*3), so:We get rid of parentheses
(x+8)*3
We multiply parentheses
3x+24
Back to the equation:
-(3x+24)
-3x-24
Back to the equation:
+(-3x-24)
2x/()-3x-24=0
We multiply all the terms by the denominator
2x-3x*()-24*()=0
We add all the numbers together, and all the variables
2x-3x*()=0
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