(x-5)(x+5)=(x-7)(x+4)

Solution for (x-5)(x+5)=(x-7)(x+4) equation:

(x-5)(x+5)=(x-7)(x+4)

We move all terms to the left:

(x-5)(x+5)-((x-7)(x+4))=0

We use the square of the difference formula

x^2-((x-7)(x+4))-25=0

We multiply parentheses ..

x^2-((+x^2+4x-7x-28))-25=0


We calculate terms in parentheses: -((+x^2+4x-7x-28)), so:

(+x^2+4x-7x-28)

We get rid of parentheses

x^2+4x-7x-28

We add all the numbers together, and all the variables

x^2-3x-28

Back to the equation:

-(x^2-3x-28)


We get rid of parentheses

x^2-x^2+3x+28-25=0

We add all the numbers together, and all the variables

3x+3=0

We move all terms containing x to the left, all other terms to the right

3x=-3

x=-3/3

x=-1