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(2x-5)=3(x-5)
We move all terms to the left:
(2x-5)-(3(x-5))=0
We get rid of parentheses
2x-(3(x-5))-5=0
We calculate terms in parentheses: -(3(x-5)), so:We get rid of parentheses
3(x-5)
We multiply parentheses
3x-15
Back to the equation:
-(3x-15)
2x-3x+15-5=0
We add all the numbers together, and all the variables
-1x+10=0
We move all terms containing x to the left, all other terms to the right
-x=-10
x=-10/-1
x=+10
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