4(2x+3)=8(x-2)

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Solution for 4(2x+3)=8(x-2) equation: 



4(2x+3)=8(x-2)

We move all terms to the left:

4(2x+3)-(8(x-2))=0

We multiply parentheses

8x-(8(x-2))+12=0



We calculate terms in parentheses: -(8(x-2)), so:

8(x-2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

8x-8x+16+12=0

We add all the numbers together, and all the variables

28!=0

There is no solution for this equation

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