(2x-5)+(3x-2)+(5-x)=180

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Solution for (2x-5)+(3x-2)+(5-x)=180 equation: 



(2x-5)+(3x-2)+(5-x)=180

We move all terms to the left:

(2x-5)+(3x-2)+(5-x)-(180)=0

We add all the numbers together, and all the variables

(2x-5)+(3x-2)+(-1x+5)-180=0

We get rid of parentheses

2x+3x-1x-5-2+5-180=0

We add all the numbers together, and all the variables

4x-182=0

We move all terms containing x to the left, all other terms to the right

4x=182

x=182/4

x=45+1/2

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