2=-1/2(-3)+b

Solution for 2=-1/2(-3)+b equation:

2=-1/2(-3)+b

We move all terms to the left:

2-(-1/2(-3)+b)=0


Domain of the equation: 2(-3)+b)!=0

b∈R


We multiply all the terms by the denominator


-(-1+2*2(-3)+b)=0


We calculate terms in parentheses: -(-1+2*2(-3)+b), so:

-1+2*2(-3)+b

determiningTheFunctionDomain
b-1+2*2(-3)

We add all the numbers together, and all the variables

b-13

Back to the equation:

-(b-13)


We get rid of parentheses

-b+13=0

We add all the numbers together, and all the variables

-1b+13=0

We move all terms containing b to the left, all other terms to the right

-b=-13

b=-13/-1

b=+13