If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2x-5)(x)=134
We move all terms to the left:
(2x-5)(x)-(134)=0
We multiply parentheses
2x^2-5x-134=0
a = 2; b = -5; c = -134;
Δ = b2-4ac
Δ = -52-4·2·(-134)
Δ = 1097
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{1097}}{2*2}=\frac{5-\sqrt{1097}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{1097}}{2*2}=\frac{5+\sqrt{1097}}{4} $
| F(x)=20/x+x | | 8x+8=158+2x | | 15+k=33 | | 75g3=147g | | 9x-4=3+8x | | 33+k=15 | | 14x+18+11+30x=148 | | 2x-3=-x+15 | | -7u/4=-21 | | 15x-(6x-3)=57 | | 2=s−1 | | 2^x^2-5x-3=8 | | 5/8y=-30 | | h−73=3 | | a÷3+7=14 | | 56=(2x-5)(x+2) | | 13x-11x-x=16 | | 6n-2=-3 | | -5.3=-9-8.9p | | 3x+2x^2-99=0 | | 0=-2x+x^2-5 | | -4x=2-4x | | 3z/7-1=-3 | | 5x÷2-2(x-1)=3x+4 | | x+2×x+(2×x)×2=99 | | 12/14x=286 | | 2(3w+3)/4=-8 | | 2x=x-1-(-5+x) | | y=32,000(1.08)1 | | a2+9=25 | | a2+9=24 | | b/4+4=10 |