(2x-4)2-3(x+1)=(x-2)4

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Solution for (2x-4)2-3(x+1)=(x-2)4 equation: 



(2x-4)2-3(x+1)=(x-2)4

We move all terms to the left:

(2x-4)2-3(x+1)-((x-2)4)=0

We multiply parentheses

4x-3x-((x-2)4)-8-3=0



We calculate terms in parentheses: -((x-2)4), so:

(x-2)4

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

x-(4x-8)-11=0

We get rid of parentheses

x-4x+8-11=0

We add all the numbers together, and all the variables

-3x-3=0

We move all terms containing x to the left, all other terms to the right

-3x=3

x=3/-3

x=-1

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