(X+3)(x+5)=(x-3)

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Solution for (X+3)(x+5)=(x-3) equation: 



(X+3)(X+5)=(X-3)

We move all terms to the left:

(X+3)(X+5)-((X-3))=0

We multiply parentheses ..

(+X^2+5X+3X+15)-((X-3))=0



We calculate terms in parentheses: -((X-3)), so:

(X-3)

We get rid of parentheses

X-3

Back to the equation:

-(X-3)



We get rid of parentheses

X^2+5X+3X-X+15+3=0

We add all the numbers together, and all the variables

X^2+7X+18=0

a = 1; b = 7; c = +18;
Δ = b2-4ac
Δ = 72-4·1·18
Δ = -23
Delta is less than zero, so there is no solution for the equation

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