(2x-4)-4(3x+8)=40

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Solution for (2x-4)-4(3x+8)=40 equation: 



(2x-4)-4(3x+8)=40

We move all terms to the left:

(2x-4)-4(3x+8)-(40)=0

We multiply parentheses

(2x-4)-12x-32-40=0

We get rid of parentheses

2x-12x-4-32-40=0

We add all the numbers together, and all the variables

-10x-76=0

We move all terms containing x to the left, all other terms to the right

-10x=76

x=76/-10

x=-7+3/5

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