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/2x-2=-x+10
We move all terms to the left:
/2x-2-(-x+10)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
/2x-(-1x+10)-2=0
We get rid of parentheses
/2x+1x-10-2=0
We multiply all the terms by the denominator
1x*2x-10*2x-2*2x+=0
We add all the numbers together, and all the variables
1x*2x-10*2x-2*2x=0
Wy multiply elements
2x^2-20x-4x=0
We add all the numbers together, and all the variables
2x^2-24x=0
a = 2; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·2·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*2}=\frac{48}{4} =12 $
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