(2x-4)(3-x)=(x+4)(2-2x)

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Solution for (2x-4)(3-x)=(x+4)(2-2x) equation: 



(2x-4)(3-x)=(x+4)(2-2x)

We move all terms to the left:

(2x-4)(3-x)-((x+4)(2-2x))=0

We add all the numbers together, and all the variables

(2x-4)(-1x+3)-((x+4)(-2x+2))=0

We multiply parentheses ..

(-2x^2+6x+4x-12)-((x+4)(-2x+2))=0



We calculate terms in parentheses: -((x+4)(-2x+2)), so:

(x+4)(-2x+2)

We multiply parentheses ..

(-2x^2+2x-8x+8)

We get rid of parentheses

-2x^2+2x-8x+8

We add all the numbers together, and all the variables

-2x^2-6x+8

Back to the equation:

-(-2x^2-6x+8)



We get rid of parentheses

-2x^2+2x^2+6x+4x+6x-12-8=0

We add all the numbers together, and all the variables

16x-20=0

We move all terms containing x to the left, all other terms to the right

16x=20

x=20/16

x=1+1/4

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