(3+(2*i))+(5-(3*i))=

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Solution for (3+(2*i))+(5-(3*i))= equation: 



(3+(2*i))+(5-(3*i))=

We move all terms to the left:

(3+(2*i))+(5-(3*i))-()=0

We add all the numbers together, and all the variables

(3+(+2i))+(5-(+3i))-()=0

We add all the numbers together, and all the variables

(3+(+2i))+(5-(+3i))=0



We calculate terms in parentheses: +(3+(+2i)), so:

3+(+2i)

determiningTheFunctionDomain
(+2i)+3

We get rid of parentheses

2i+3

Back to the equation:

+(2i+3)





We calculate terms in parentheses: +(5-(+3i)), so:

5-(+3i)

determiningTheFunctionDomain
-(+3i)+5

We get rid of parentheses

-3i+5

Back to the equation:

+(-3i+5)



We get rid of parentheses

2i-3i+3+5=0

We add all the numbers together, and all the variables

-1i+8=0

We move all terms containing i to the left, all other terms to the right

-i=-8

i=-8/-1

i=+8

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