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(2x-3)-(4+5x)=5-2(x+3)
We move all terms to the left:
(2x-3)-(4+5x)-(5-2(x+3))=0
We add all the numbers together, and all the variables
(2x-3)-(5x+4)-(5-2(x+3))=0
We get rid of parentheses
2x-5x-(5-2(x+3))-3-4=0
We calculate terms in parentheses: -(5-2(x+3)), so:We add all the numbers together, and all the variables
5-2(x+3)
determiningTheFunctionDomain -2(x+3)+5
We multiply parentheses
-2x-6+5
We add all the numbers together, and all the variables
-2x-1
Back to the equation:
-(-2x-1)
-3x-(-2x-1)-7=0
We get rid of parentheses
-3x+2x+1-7=0
We add all the numbers together, and all the variables
-1x-6=0
We move all terms containing x to the left, all other terms to the right
-x=6
x=6/-1
x=-6
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