10(x+2)=20(4-x)

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Solution for 10(x+2)=20(4-x) equation: 



10(x+2)=20(4-x)

We move all terms to the left:

10(x+2)-(20(4-x))=0

We add all the numbers together, and all the variables

10(x+2)-(20(-1x+4))=0

We multiply parentheses

10x-(20(-1x+4))+20=0



We calculate terms in parentheses: -(20(-1x+4)), so:

20(-1x+4)

We multiply parentheses

-20x+80

Back to the equation:

-(-20x+80)



We get rid of parentheses

10x+20x-80+20=0

We add all the numbers together, and all the variables

30x-60=0

We move all terms containing x to the left, all other terms to the right

30x=60

x=60/30

x=2

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