(2x-3)+(5+x)=(7x+1)-(3-7x)

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Solution for (2x-3)+(5+x)=(7x+1)-(3-7x) equation: 



(2x-3)+(5+x)=(7x+1)-(3-7x)

We move all terms to the left:

(2x-3)+(5+x)-((7x+1)-(3-7x))=0

We add all the numbers together, and all the variables

(2x-3)+(x+5)-((7x+1)-(-7x+3))=0

We get rid of parentheses

2x+x-((7x+1)-(-7x+3))-3+5=0



We calculate terms in parentheses: -((7x+1)-(-7x+3)), so:

(7x+1)-(-7x+3)

We get rid of parentheses

7x+7x+1-3

We add all the numbers together, and all the variables

14x-2

Back to the equation:

-(14x-2)



We add all the numbers together, and all the variables

3x-(14x-2)+2=0

We get rid of parentheses

3x-14x+2+2=0

We add all the numbers together, and all the variables

-11x+4=0

We move all terms containing x to the left, all other terms to the right

-11x=-4

x=-4/-11

x=4/11

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