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(2x-3)(5x+1)=2x+(2/5)
We move all terms to the left:
(2x-3)(5x+1)-(2x+(2/5))=0
We add all the numbers together, and all the variables
(2x-3)(5x+1)-(2x+(+2/5))=0
We multiply parentheses ..
(+10x^2+2x-15x-3)-(2x+(+2/5))=0
We multiply all the terms by the denominator
((+10x^2+2x-15x-3))*5))-(2x+(+2=0
We move all terms containing x to the left, all other terms to the right
((+10x^2+2x-15x-3))*5))-(2x+(=-2
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