(2x-3)(4x-6)=0

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Solution for (2x-3)(4x-6)=0 equation: 



(2x-3)(4x-6)=0

We multiply parentheses ..

(+8x^2-12x-12x+18)=0

We get rid of parentheses

8x^2-12x-12x+18=0

We add all the numbers together, and all the variables

8x^2-24x+18=0

a = 8; b = -24; c = +18;
Δ = b2-4ac
Δ = -242-4·8·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{24}{16}=1+1/2$

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