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(5x-1)(-20x+4)=0
We multiply parentheses ..
(-100x^2+20x+20x-4)=0
We get rid of parentheses
-100x^2+20x+20x-4=0
We add all the numbers together, and all the variables
-100x^2+40x-4=0
a = -100; b = 40; c = -4;
Δ = b2-4ac
Δ = 402-4·(-100)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-40}{-200}=1/5$
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