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(2x-3)(3x+1)=(6x-1)(x+5)
We move all terms to the left:
(2x-3)(3x+1)-((6x-1)(x+5))=0
We multiply parentheses ..
(+6x^2+2x-9x-3)-((6x-1)(x+5))=0
We calculate terms in parentheses: -((6x-1)(x+5)), so:We get rid of parentheses
(6x-1)(x+5)
We multiply parentheses ..
(+6x^2+30x-1x-5)
We get rid of parentheses
6x^2+30x-1x-5
We add all the numbers together, and all the variables
6x^2+29x-5
Back to the equation:
-(6x^2+29x-5)
6x^2-6x^2+2x-9x-29x-3+5=0
We add all the numbers together, and all the variables
-36x+2=0
We move all terms containing x to the left, all other terms to the right
-36x=-2
x=-2/-36
x=1/18
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