(2x-29)=(10x+5)=180

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Solution for (2x-29)=(10x+5)=180 equation: 



(2x-29)=(10x+5)=180

We move all terms to the left:

(2x-29)-((10x+5))=0

We get rid of parentheses

2x-((10x+5))-29=0



We calculate terms in parentheses: -((10x+5)), so:

(10x+5)

We get rid of parentheses

10x+5

Back to the equation:

-(10x+5)



We get rid of parentheses

2x-10x-5-29=0

We add all the numbers together, and all the variables

-8x-34=0

We move all terms containing x to the left, all other terms to the right

-8x=34

x=34/-8

x=-4+1/4

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