13=1/3(x+9)

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Solution for 13=1/3(x+9) equation: 



13=1/3(x+9)

We move all terms to the left:

13-(1/3(x+9))=0



Domain of the equation: 3(x+9))!=0

x∈R



We multiply all the terms by the denominator


-(1+13*3(x+9))=0



We calculate terms in parentheses: -(1+13*3(x+9)), so:

1+13*3(x+9)

determiningTheFunctionDomain
13*3(x+9)+1

Wy multiply elements

39x(x+1

Back to the equation:

-(39x(x+1)





We calculate terms in parentheses: -(39x(x+1), so:

39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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39x(x+1





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